Question

factor\
r² -16r + 60\
(r - 6)(r + 10)\
(r - 6)(r - 10)\
(r +30)(r - 2)\
(r - 15)(r + 4)

Explanation:

Step1: Identify $a,b,c$ for $ax^2+bx+c$

For $r^2 -16r +60$, $a=1$, $b=-16$, $c=60$

Step2: Find pair with sum $b$, product $ac$

Need two numbers: sum $=-16$, product $=1\times60=60$. The numbers are $-6$ and $-10$.

Step3: Split middle term and factor

$r^2 -6r -10r +60 = r(r-6)-10(r-6)=(r-6)(r-10)$

Answer:

(r - 6)(r - 10)