Question

factor completely.
$5t^{3} - 10t^{2} + 9t - 18$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(5t^3 - 10t^2)+(9t - 18)$

Step2: Factor out GCF from each group

Factor out $5t^2$ from the first group and 9 from the second group: $5t^2(t - 2)+9(t - 2)$

Step3: Factor out the common binomial factor

Factor out $(t - 2)$: $(t - 2)(5t^2 + 9)$

Answer:

$(t - 2)(5t^2 + 9)$