Question

factor completely.
$14g^{3}-7g^{2}+3 - 6g$

Explanation:

Step1: Group terms for factoring

Group the first two and last two terms:
$(14g^3 - 7g^2) + (3 - 6g)$

Step2: Factor out GCF from each group

Factor $7g^2$ from first group, $-3$ from second group:
$7g^2(2g - 1) - 3(2g - 1)$

Step3: Factor out common binomial

Factor out $(2g - 1)$ from both terms:
$(2g - 1)(7g^2 - 3)$

Answer:

$(2g - 1)(7g^2 - 3)$