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factor completely. 49p² - 121

Question

factor completely.
49p² - 121

Explanation:

Step1: Recognize difference of squares

$49p^2 = (7p)^2$, $121 = 11^2$

Step2: Apply difference of squares formula

Use $a^2 - b^2 = (a-b)(a+b)$:
$(7p)^2 - 11^2 = (7p-11)(7p+11)$

Answer:

$(7p - 11)(7p + 11)$