Question

factor completely.
$18j^{3} + 18j^{2} + 7j + 7$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(18j^3 + 18j^2) + (7j + 7)$

Step2: Factor out the GCF from each group

Factor out $18j^2$ from the first group and $7$ from the second group: $18j^2(j + 1) + 7(j + 1)$

Step3: Factor out the common binomial factor

Factor out $(j + 1)$ from the expression: $(j + 1)(18j^2 + 7)$

Answer:

$(j + 1)(18j^2 + 7)$