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Question
factor completely
$a^2 + 10a + 24$
$4(a + 6)(a + 9)$
not factorable
$(a + 4)(a + 6)$
$6(a + 7)(a +$
Step1: Find pair summing to 10, product 24
Identify two numbers: $4$ and $6$, since $4+6=10$ and $4\times6=24$.
Step2: Split middle term and factor
Rewrite and factor the quadratic:
$$a^2 + 4a + 6a + 24 = a(a+4) + 6(a+4) = (a+4)(a+6)$$
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C. $(a + 4)(a + 6)$