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factor by grouping. $5y^{3}+6y^{2}+35y+42$

Question

factor by grouping.
$5y^{3}+6y^{2}+35y+42$

Explanation:

Step1: Group terms into pairs

$(5y^3 + 6y^2) + (35y + 42)$

Step2: Factor GCF from each pair

$y^2(5y + 6) + 7(5y + 6)$

Step3: Factor out common binomial

$(5y + 6)(y^2 + 7)$

Answer:

$(5y + 6)(y^2 + 7)$