QUESTION IMAGE
Question
factoring practice
- $6x^3 - 12x$
- $5x^2 - 5y^2$
- $x^2 + xy - 12y^2$
- $18x^2 - 25x - 3$
- $x^4 - 64$
- $3x - 9xy$
- $x^2 + 9x + 20$
- $-4 + 25x^2$
- $9x^4 - 16y^2$
- $3y^2 - 9y^3$
- $9x^2 + 1$
- $2x^2 - 4xy + 8x$
- $m^4 - 6m^2 - 27$
- $4x^2 + 24x + 36$
- $9y^2 - 30y + 25$
- $-75 + 12x^4$
- $y^4 - 17y^2 + 16$
- $x^4 + 4x - 21$
- $3x^5 + 15x^3 + 12x$
- $3x^2 yz^3 + 18xy^2$
- $6xy + 3x - 4y - 2$
- $z^4 - 20z^2 + 100$
- $m^2 + 6m + 9 - 4n^2$
- $16y^2 - a^2 - 6ab - 9b^2$
- $m^4 + 3m^2 + 4$
Step1: Factor out GCF (Q1)
$6x^3 - 12x = 6x(x^2 - 2)$
Step2: Factor difference of squares (Q2)
$5x^2 - 5y^2 = 5(x^2 - y^2) = 5(x-y)(x+y)$
Step3: Factor quadratic trinomial (Q3)
$x^2 + xy -12y^2 = (x-3y)(x+4y)$
Step4: Factor quadratic trinomial (Q4)
$18x^2 -25x -3 = (9x+1)(2x-3)$
Step5: Factor difference of squares (Q5)
$x^4 -64 = (x^2-8)(x^2+8) = (x-2\sqrt{2})(x+2\sqrt{2})(x^2+8)$
Step6: Factor out GCF (Q6)
$3x -9xy = 3x(1-3y)$
Step7: Factor quadratic trinomial (Q7)
$x^2 +9x +20 = (x+4)(x+5)$
Step8: Factor difference of squares (Q8)
$-4 +25x^2 = 25x^2 -4 = (5x-2)(5x+2)$
Step9: Factor difference of squares (Q9)
$9x^4 -16y^2 = (3x^2-4y)(3x^2+4y)$
Step10: Factor out GCF (Q10)
$3y^5 -9y^3 = 3y^3(y^2 -3)$
Step11: State non-factorable (Q11)
$9x^2 +1$ is irreducible over reals
Step12: Factor out GCF (Q12)
$2x^2 -4xy +8x = 2x(x-2y+4)$
Step13: Substitute & factor (Q13)
Let $u=m^2$: $u^2-6u-27=(u-9)(u+3)=(m^2-9)(m^2+3)=(m-3)(m+3)(m^2+3)$
Step14: Factor perfect square (Q14)
$4x^2 +24x +36 = 4(x^2+6x+9)=4(x+3)^2$
Step15: Factor perfect square (Q15)
$9y^2 -30y +25 = (3y-5)^2$
Step16: Factor difference of squares (Q16)
$-75+12x^4=12x^4-75=3(4x^4-25)=3(2x^2-5)(2x^2+5)$
Step17: Substitute & factor (Q17)
Let $u=y^2$: $u^2-17u+16=(u-1)(u-16)=(y^2-1)(y^2-16)=(y-1)(y+1)(y-4)(y+4)$
Step18: Factor quadratic trinomial (Q18)
$x^2 +4x -21 = (x+7)(x-3)$
Step19: Factor out GCF & trinomial (Q19)
$3x^5+15x^3+12x=3x(x^4+5x^2+4)=3x(x^2+1)(x^2+4)$
Step20: Factor out GCF (Q20)
$3x^2yz^3 +18xy^2 = 3xy(xz^3 +6y)$
Step21: Factor by grouping (Q21)
$6xy+3x-4y-2=3x(2y+1)-2(2y+1)=(3x-2)(2y+1)$
Step22: Substitute & perfect square (Q22)
Let $u=z^2$: $u^2-20u+100=(u-10)^2=(z^2-10)^2$
Step23: Factor by grouping (Q23)
$m^2+6m+9-4n^2=(m+3)^2-(2n)^2=(m+3-2n)(m+3+2n)$
Step24: Factor by grouping (Q24)
$16y^2 -a^2-6ab-9b^2=16y^2-(a+3b)^2=(4y-a-3b)(4y+a+3b)$
Step25: Rewrite & factor (Q25)
$m^4+3m^2+4=m^4+4m^2+4-m^2=(m^2+2)^2-m^2=(m^2+m+2)(m^2-m+2)$
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