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farmers wishing to avoid the use of purchased seeds are increasingly co…

Question

farmers wishing to avoid the use of purchased seeds are increasingly concerned about inadvertently growing hybrid plants as a result of pollen drifting from nearby farms. assuming that these farmers raise their own seeds, the fractional portion of their crop that remains free of hybrid plants t years later can be approximated by (p(t)=(0.93)^t). a) using this model, predict the fractional portion of the crop that will be free of hybrid plants 5 yr after a neighboring farm begins to use purchased seeds. b) find (p(5)) and explain its meaning. c) when will half of the crop be hybrid plants? a) after 5 yr, (square%) of the crop will be free of hybrid plants (round to the nearest integer as needed.)

Explanation:

Step1: Substitute $t = 5$ into $P(t)$

We are given $P(t)=(0.93)^t$. Substituting $t = 5$ gives $P(5)=(0.93)^5$.

Step2: Calculate $(0.93)^5$

$(0.93)^5=0.93\times0.93\times0.93\times0.93\times0.93\approx0.696$.

Step3: Convert to percentage

To convert to a percentage, we multiply by 100. So $0.696\times100 = 69.6\%\approx70\%$.

Step4: Find the derivative of $P(t)$

The derivative of $y = a^t$ with respect to $t$ is $y^\prime=a^t\ln(a)$. For $P(t)=(0.93)^t$, $P^\prime(t)=(0.93)^t\ln(0.93)$.

Step5: Evaluate $P^\prime(5)$

$P^\prime(5)=(0.93)^5\ln(0.93)$. We know $(0.93)^5\approx0.696$ and $\ln(0.93)\approx - 0.0725$. So $P^\prime(5)\approx0.696\times(- 0.0725)\approx - 0.0505$. The negative sign means the fraction of non - hybrid plants is decreasing at $t = 5$ years, and the magnitude $0.0505$ represents the rate of decrease of the fraction of non - hybrid plants per year at $t = 5$ years.

Step6: Solve for $t$ when half of the crop is hybrid

If half of the crop is hybrid, then the fraction of non - hybrid plants $P(t)=0.5$. So we set $(0.93)^t = 0.5$.

Step7: Take the natural logarithm of both sides

$\ln((0.93)^t)=\ln(0.5)$. Using the property $\ln(a^b)=b\ln(a)$, we get $t\ln(0.93)=\ln(0.5)$.

Step8: Solve for $t$

$t=\frac{\ln(0.5)}{\ln(0.93)}\approx\frac{-0.6931}{-0.0725}\approx9.56$ years.

Answer:

a) $70$
b) $P^\prime(5)\approx - 0.0505$. It means the fraction of non - hybrid plants is decreasing at a rate of approximately $0.0505$ per year at $t = 5$ years.
c) Approximately $9.56$ years.