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Question
- felix said quadrilateral abcd is a parallelogram because be = de. what was his error?
To determine a quadrilateral is a parallelogram, the diagonals must bisect each other, meaning both \( BE = DE \) AND \( AE = CE \). Felix only considered \( BE = DE \), ignoring the other pair of segments (\( AE \) and \( CE \)) of the diagonals. Just one part of the diagonal - bisecting condition being met is not sufficient to prove \( ABCD \) is a parallelogram.
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Felix's error was that for a quadrilateral to be a parallelogram, its diagonals must bisect each other (i.e., \( BE = DE \) and \( AE = CE \)). He only verified \( BE = DE \) and did not check if \( AE = CE \), so having just \( BE = DE \) is not enough to conclude \( ABCD \) is a parallelogram.