Question

for the few questions in this set, you will see the quadratic formula. soon, you will need to answer the questions without this reminder.
$x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }$
for $ax^2 + bx + c = 0$

solve for x. write both solutions, separated by a comma.
$2x^2 - 5x + 2 = 0$
enter the correct answer.

Explanation:

Step1: Identify a, b, c values

From $2x^2 -5x +2=0$, $a=2$, $b=-5$, $c=2$

Step2: Calculate discriminant

$\sqrt{b^2-4ac} = \sqrt{(-5)^2 - 4(2)(2)} = \sqrt{25-16} = \sqrt{9}=3$

Step3: Apply quadratic formula

$x=\frac{-(-5)\pm3}{2(2)}=\frac{5\pm3}{4}$

Step4: Solve for both roots

First root: $\frac{5+3}{4}=\frac{8}{4}=2$
Second root: $\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

Answer:

$2, \frac{1}{2}$