Question

the figure above shows the path of a ball tossed from a building. air resistance is ignored. in the figure above, the magnitude of the balls velocity is greatest at location
oc.
ob.
oa.
od.
question 2
what is the path of a projectile (in the absence of friction)?
a wavy line
a parabola
projectiles do not follow a predictable path.
a hyperbola

Explanation:

Step1: Analyze velocity components

The horizontal component of velocity ($v_x$) remains constant as there is no horizontal acceleration (air - resistance is ignored). The vertical component of velocity ($v_y$) changes due to gravity. At the highest point of the projectile motion (point B), the vertical component of velocity is 0. At point A, the ball has an initial vertical and horizontal velocity component. As the ball falls from point B to point D, the vertical component of velocity increases in the downward direction.

Step2: Calculate magnitude of velocity

The magnitude of the velocity $v = \sqrt{v_x^{2}+v_y^{2}}$. At point D, $v_x$ is non - zero (constant throughout the motion) and $v_y$ has its maximum magnitude in the downward direction among all the points A, B, C, and D. So the magnitude of the velocity is greatest at point D.

For the second question:
The path of a projectile in the absence of friction is a parabola. This is because the horizontal motion is a uniform motion with constant velocity ($x = v_{0x}t$) and the vertical motion is a uniformly accelerated motion ($y=v_{0y}t-\frac{1}{2}gt^{2}$). Combining these two equations gives a parabolic equation.

Answer:

Question 1: D. OD
Question 2: a parabola