Question

in the figure below, m∠jkm = 81°, m∠nkm = 28°, and (overline{kn}) bisects ∠lkm. find m∠jkl. m∠jkl = (square^{circ})

Explanation:

Step1: Find m∠LKM

Since $\overline{KN}$ bisects $\angle LKM$ and $m\angle NKM = 28^{\circ}$, then $m\angle LKM=2\times m\angle NKM$.
$m\angle LKM = 2\times28^{\circ}=56^{\circ}$

Step2: Find m∠JKL

We know that $m\angle JKL=m\angle JKM - m\angle LKM$. Given $m\angle JKM = 81^{\circ}$ and $m\angle LKM = 56^{\circ}$.
$m\angle JKL=81^{\circ}- 56^{\circ}=25^{\circ}$

Answer:

$25^{\circ}$