QUESTION IMAGE
Question
in the figure below, k lies between j and l. find the location of k so that jk is $\frac{2}{9}$ of jl. j - 30 k? l 6 location of k :
Step1: Calculate the length of JL
$JL=6 - (-30)=36$
Step2: Calculate the length of JK
$JK=\frac{2}{9}\times JL=\frac{2}{9}\times36 = 8$
Step3: Find the location of K
Let the location of K be $x$. Since $JK=x - (-30)$ and $JK = 8$, then $x+30 = 8$, so $x=8 - 30=-22$
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$-22$