QUESTION IMAGE
Question
in the figure below, m∠wxz = 108°, and m∠1 is three times m∠2. find m∠2.
Step1: Set up an equation
Let $m\angle2 = x$. Then $m\angle1=3x$. Since $m\angle WXZ=m\angle1 + m\angle2$ and $m\angle WXZ = 108^{\circ}$, we have the equation $3x + x=108$.
Step2: Combine like - terms
Combining the left - hand side of the equation $3x + x$, we get $4x = 108$.
Step3: Solve for x
Dividing both sides of the equation $4x = 108$ by 4, we have $x=\frac{108}{4}=27$.
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$27^{\circ}$