Question

in the figure below, m∠wxz = 63°, and m∠2 is 19° more than m∠1. find m∠1.

Explanation:

Step1: Set up an equation

Let $m\angle1 = x$. Then $m\angle2=x + 19$. Since $m\angle WXZ=m\angle1 + m\angle2$ and $m\angle WXZ = 63^{\circ}$, we have the equation $x+(x + 19)=63$.

Step2: Simplify the left - hand side of the equation

Combining like terms, we get $2x+19 = 63$.

Step3: Isolate the variable term

Subtract 19 from both sides: $2x=63 - 19$, so $2x=44$.

Step4: Solve for x

Divide both sides by 2: $x=\frac{44}{2}=22$.

Answer:

$22$