Question

6
fill in the blank 1 point
watch help video #4
fill in the blank to complete the numerator and denominator for the pr
$\frac{6j^{-7}k}{16j^{-3}k^{-5}}$
numerator: type your answer
denominator: type your answer

Explanation:

Step1: Simplify coefficients

$\frac{6}{16} = \frac{3}{8}$

Step2: Simplify $j$ terms

$j^{-7 - (-3)} = j^{-7+3} = j^{-4} = \frac{1}{j^4}$

Step3: Simplify $k$ terms

$k^{1 - (-5)} = k^{1+5} = k^6$

Step4: Combine all simplified parts

$\frac{3}{8} \times \frac{k^6}{j^4} = \frac{3k^6}{8j^4}$

Answer:

Numerator: $3k^6$
Denominator: $8j^4$