Question

fill in the table using this function rule.
$y = 3x - 4$

x	y
-6	\square
-3	\square
0	\square
3	\square

Explanation:

Step1: Substitute \( x = -6 \) into \( y = 3x - 4 \)

\( y = 3\times(-6) - 4 = -18 - 4 = -22 \)

Step2: Substitute \( x = -3 \) into \( y = 3x - 4 \)

\( y = 3\times(-3) - 4 = -9 - 4 = -13 \)

Step3: Substitute \( x = 0 \) into \( y = 3x - 4 \)

\( y = 3\times0 - 4 = 0 - 4 = -4 \)

Step4: Substitute \( x = 3 \) into \( y = 3x - 4 \)

\( y = 3\times3 - 4 = 9 - 4 = 5 \)

Answer:

When \( x = -6 \), \( y = -22 \); when \( x = -3 \), \( y = -13 \); when \( x = 0 \), \( y = -4 \); when \( x = 3 \), \( y = 5 \)

So the filled table (row by row for \( y \)) is: \(-22\), \(-13\), \(-4\), \(5\)