Question

final exam (precalculus)
score: 24/25 answered: 24/25
question 25
simplify $\frac{sec(t)}{csc(t)}$ to a single trig function with no fractions.

Explanation:

Step1: Recall trig identities

$\sec(t)=\frac{1}{\cos(t)}$, $\csc(t)=\frac{1}{\sin(t)}$.

Step2: Substitute and simplify

$\frac{\sec(t)}{\csc(t)}=\frac{\frac{1}{\cos(t)}}{\frac{1}{\sin(t)}}=\frac{\sin(t)}{\cos(t)}=\tan(t)$.

Answer:

$\tan(t)$