Question

find the area of the figure below, composed of a parallelogram and one semicircle. rounded to the nearest tenths place

Explanation:

Step1: Calculate parallelogram area

The area formula for a parallelogram is $A = base\times height$. Here, the base is 18 and the height is 11. So, $A_{parallelogram}=18\times11 = 198$.

Step2: Calculate semi - circle area

The area formula for a full - circle is $A=\pi r^{2}$, and for a semi - circle it is $A=\frac{1}{2}\pi r^{2}$. The radius $r = 11\div2=5.5$. Then $A_{semicircle}=\frac{1}{2}\times\pi\times(5.5)^{2}=\frac{1}{2}\times\pi\times30.25\approx47.5$.

Step3: Calculate total area

The total area of the figure is the sum of the area of the parallelogram and the area of the semi - circle. $A = A_{parallelogram}+A_{semicircle}=198 + 47.5=245.5$.

Answer:

$245.5$