Question

find the area of the figure below, composed of a rectangle and one semicircle, with another semicircle removed. round to the nearest tenths place.

Explanation:

Step1: Calculate area of rectangle

The rectangle has length $l = 10$ and width $w=4$. The area of a rectangle is $A_{rect}=l\times w$. So $A_{rect}=10\times4 = 40$.

Step2: Analyze semi - circles

The two semi - circles have the same radius $r = \frac{4}{2}=2$. The area of a full circle is $A=\pi r^{2}$, and since the two semi - circles cancel each other out (one is added and one is removed), their net contribution to the area of the figure is 0.

Answer:

$40.0$