Question

find the area of the figure. (sides meet at right angles.)

Explanation:

Step1: Divide the figure into rectangles

We can divide the given figure into two rectangles. One rectangle has dimensions \(5\ m\times(4 + 2)\ m\) and the other has dimensions \(2\ m\times(4 + 2+ 4)\ m\).

Step2: Calculate area of first rectangle

The area of a rectangle is \(A = l\times w\). For the first rectangle with length \(l = 5\ m\) and width \(w=(4 + 2)=6\ m\), the area \(A_1=5\times6 = 30\ m^{2}\).

Step3: Calculate area of second rectangle

For the second rectangle with length \(l = 2\ m\) and width \(w=(4 + 2+ 4)=10\ m\), the area \(A_2=2\times10 = 20\ m^{2}\).

Step4: Calculate total area

The total area of the figure \(A = A_1+A_2\). So \(A=30 + 20=50\ m^{2}\).

Answer:

\(50\ m^{2}\)