Question

find the area of the figure. (sides meet at right angles.)

Explanation:

Step1: Find area of large rectangle

The large rectangle has length $l = 11$m and height $h=6$m. The area of a rectangle is $A = l\times h$. So the area of the large rectangle $A_{1}=11\times6 = 66$m².

Step2: Find area of the small - cut out rectangle

The small rectangle has length $l = 3$m and height $h = 3$m. The area of the small rectangle $A_{2}=3\times3=9$m².

Step3: Find area of the figure

The area of the given figure $A = A_{1}-A_{2}$.
$A=66 - 9=57$m².

Answer:

$57$