Question

find the area of the following triangle:
image of a triangle with side lengths 11, 16, 14 and a height of 10 (dashed line) to the side of length 16, with a right angle mark
note: figure may not be drawn to scale.
label optional

Explanation:

Step1: Identify base and height

The triangle has a side of length 16 (base) and a corresponding height of 10 (perpendicular to the base).

Step2: Apply area formula for triangle

The formula for the area of a triangle is $A = \frac{1}{2} \times \text{base} \times \text{height}$. Substituting base = 16 and height = 10, we get $A = \frac{1}{2} \times 16 \times 10$.

Step3: Calculate the area

First, multiply 16 and 10: $16 \times 10 = 160$. Then, multiply by $\frac{1}{2}$: $\frac{1}{2} \times 160 = 80$.

Answer:

80