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find the discriminant. $w^2 + 4w + 4 = 0$

Question

find the discriminant.
$w^2 + 4w + 4 = 0$

Explanation:

Step1: Recall discriminant formula

For a quadratic equation \(ax^2 + bx + c = 0\), the discriminant \(D\) is given by \(D = b^2 - 4ac\).

Step2: Identify coefficients

In the equation \(w^2 + 4w + 4 = 0\), we have \(a = 1\), \(b = 4\), and \(c = 4\).

Step3: Calculate discriminant

Substitute the values into the formula: \(D = 4^2 - 4\times1\times4\)
\(= 16 - 16\)
\(= 0\)

Answer:

\(0\)