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find the distance, d, of $overline{ab}$. a = (-7, -7) b = (-3, -1) d = …

Question

find the distance, d, of $overline{ab}$. a = (-7, -7) b = (-3, -1) d = ? d = $sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$ round to the nearest tenth.

Explanation:

Step1: Identify coordinates

Let $(x_1,y_1)=(-7,-7)$ and $(x_2,y_2)=(-3,-1)$.

Step2: Substitute into distance formula

$d=\sqrt{(-3 - (-7))^{2}+(-1-(-7))^{2}}=\sqrt{( - 3 + 7)^{2}+(-1 + 7)^{2}}=\sqrt{4^{2}+6^{2}}$.

Step3: Calculate squares and sum

$d=\sqrt{16 + 36}=\sqrt{52}$.

Step4: Approximate the value

$d\approx7.2$.

Answer:

$7.2$