Question

1. find the distance between j(-2, 6) and k(-8, -3).

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.

Step2: Identify coordinates

Let $(x_1,y_1)=(-2,6)$ and $(x_2,y_2)=(-8,-3)$.

Step3: Substitute values

$d=\sqrt{(-8 - (-2))^2+(-3 - 6)^2}=\sqrt{(-8 + 2)^2+(-9)^2}=\sqrt{(-6)^2+81}=\sqrt{36 + 81}=\sqrt{117}=3\sqrt{13}$.

Answer:

$3\sqrt{13}$