Question

find each sum.$(3n^{2}-5n+6)+(-8n^{2}-3n-2)=LXB0-11n^{2}-2n+4LXB1-5n^{2}-2n-4$done

Explanation:

Step1: Combine $n^2$ terms

$3n^2 + (-8n^2) = (3-8)n^2 = -5n^2$

Step2: Combine $n$ terms

$-5n + (-3n) = (-5-3)n = -8n$

Step3: Combine constant terms

$6 + (-2) = 6-2 = 4$

Step4: Sum all combined terms

$-5n^2 -8n +4$

Answer:

$\boldsymbol{-5n^2 - 8n + 4}$ (the third option)