Question

find the first five terms of the arithmetic sequence given that $a_1 = 4$, $d = 3$ 7, 49, 343, 2401, 16807 4, 7, 10, 13, 16 4, 12, 36, 144, 576 3, 7, 11, 15, 19

Explanation:

Step1: Recall arithmetic sequence formula

The nth term of an arithmetic sequence is given by $a_n = a_1 + (n-1)d$, where $a_1$ is the first term, $d$ is the common difference.

Step2: Calculate 2nd term

Substitute $n=2$, $a_1=4$, $d=3$:
$a_2 = 4 + (2-1)\times3 = 4+3=7$

Step3: Calculate 3rd term

Substitute $n=3$, $a_1=4$, $d=3$:
$a_3 = 4 + (3-1)\times3 = 4+6=10$

Step4: Calculate 4th term

Substitute $n=4$, $a_1=4$, $d=3$:
$a_4 = 4 + (4-1)\times3 = 4+9=13$

Step5: Calculate 5th term

Substitute $n=5$, $a_1=4$, $d=3$:
$a_5 = 4 + (5-1)\times3 = 4+12=16$

Answer:

B. 4, 7, 10, 13, 16