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Question
d) if $f(x) = -13 + 7x$ ; find the following.
- $2f(8) + 7f(2)$ = __________
- $\frac{f(13)}{4f(3)}$ = __________
- $-3f(1) \times f(-2)$ = __________
- $-4f(9) - 6f(0)$ = __________
1) Solve \( 2f(8)+7f(2) \)
Step 1: Find \( f(8) \)
Substitute \( x = 8 \) into \( f(x)=-13 + 7x \).
\( f(8)=-13 + 7\times8=-13 + 56 = 43 \)
Step 2: Find \( f(2) \)
Substitute \( x = 2 \) into \( f(x)=-13 + 7x \).
\( f(2)=-13 + 7\times2=-13 + 14 = 1 \)
Step 3: Calculate \( 2f(8)+7f(2) \)
Substitute \( f(8) = 43 \) and \( f(2)=1 \) into the expression.
\( 2\times43+7\times1 = 86 + 7=93 \)
2) Solve \( \frac{f(13)}{4f(3)} \)
Step 1: Find \( f(13) \)
Substitute \( x = 13 \) into \( f(x)=-13 + 7x \).
\( f(13)=-13 + 7\times13=-13 + 91 = 78 \)
Step 2: Find \( f(3) \)
Substitute \( x = 3 \) into \( f(x)=-13 + 7x \).
\( f(3)=-13 + 7\times3=-13 + 21 = 8 \)
Step 3: Calculate \( \frac{f(13)}{4f(3)} \)
Substitute \( f(13) = 78 \) and \( f(3)=8 \) into the expression.
\( \frac{78}{4\times8}=\frac{78}{32}=\frac{39}{16}=2.4375 \)
3) Solve \( -3f(1)\times f(-2) \)
Step 1: Find \( f(1) \)
Substitute \( x = 1 \) into \( f(x)=-13 + 7x \).
\( f(1)=-13 + 7\times1=-13 + 7=-6 \)
Step 2: Find \( f(-2) \)
Substitute \( x=-2 \) into \( f(x)=-13 + 7x \).
\( f(-2)=-13 + 7\times(-2)=-13-14=-27 \)
Step 3: Calculate \( -3f(1)\times f(-2) \)
Substitute \( f(1)=-6 \) and \( f(-2)=-27 \) into the expression.
\( -3\times(-6)\times(-27)=18\times(-27)=-486 \)
4) Solve \( -4f(9)-6f(0) \)
Step 1: Find \( f(9) \)
Substitute \( x = 9 \) into \( f(x)=-13 + 7x \).
\( f(9)=-13 + 7\times9=-13 + 63 = 50 \)
Step 2: Find \( f(0) \)
Substitute \( x = 0 \) into \( f(x)=-13 + 7x \).
\( f(0)=-13 + 7\times0=-13 \)
Step 3: Calculate \( -4f(9)-6f(0) \)
Substitute \( f(9) = 50 \) and \( f(0)=-13 \) into the expression.
\( -4\times50-6\times(-13)=-200 + 78=-122 \)
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s:
- \( \boldsymbol{93} \)
- \( \boldsymbol{\frac{39}{16}} \) (or \( 2.4375 \))
- \( \boldsymbol{-486} \)
- \( \boldsymbol{-122} \)