Question

find the intercepts of the equation $4x + 2y = 8$.

select one:
a. $x$-intercept: $(2,0)$, $y$-intercept: $(0,4)$
b. $x$-intercept: $(4,0)$, $y$-intercept: $(0,2)$
c. $x$-intercept: $(0,2)$, $y$-intercept: $(4,0)$
d. $x$-intercept: $(0,4)$, $y$-intercept: $(2,0)$

Explanation:

Step1: Find x-intercept (set y=0)

Substitute $y=0$ into $4x+2y=8$:
$$4x + 2(0) = 8$$
$$4x = 8$$
$$x = \frac{8}{4} = 2$$
So x-intercept is $(2,0)$.

Step2: Find y-intercept (set x=0)

Substitute $x=0$ into $4x+2y=8$:
$$4(0) + 2y = 8$$
$$2y = 8$$
$$y = \frac{8}{2} = 4$$
So y-intercept is $(0,4)$.

Answer:

A. $x$-intercept: $(2,0)$, $y$-intercept: $(0,4)$