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find the length of the missing sides of the right triangle in the below…

Question

find the length of the missing sides of the right triangle in the below figure.
figure of a right triangle with hypotenuse 37, base x, height 3x - 1, and right angle at the intersection of base and height
a. height: 25, base: 12
b. height: 35, base: 12
c. height: 12, base: 35
d. height: 12, base: 25

Explanation:

Step1: Apply Pythagorean theorem

$$x^2 + (3x-1)^2 = 37^2$$

Step2: Expand and simplify equation

$$x^2 + 9x^2 -6x +1 = 1369$$
$$10x^2 -6x -1368 = 0$$
$$5x^2 -3x -684 = 0$$

Step3: Solve quadratic equation

Use quadratic formula $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$, where $a=5$, $b=-3$, $c=-684$:
$$x=\frac{3\pm\sqrt{9 + 13680}}{10}=\frac{3\pm\sqrt{13689}}{10}=\frac{3\pm117}{10}$$
Take positive root: $x=\frac{3+117}{10}=12$

Step4: Calculate height

$$3x-1=3(12)-1=35$$

Answer:

B. Height: 35, Base: 12