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find the measure $mk = 24, jl = 20$, and $m\\angle mjl = 50^\\circ$ $nk…

Question

find the measure
$mk = 24, jl = 20$, and $m\angle mjl = 50^\circ$
$nk = \underline{\quad\quad}$
$m\angle knl = \underline{\quad\quad}$
$nl = \underline{\quad\quad}$
$m\angle kjl = \underline{\quad\quad}$
$ml = \underline{\quad\quad}$
$m\angle mlk = \underline{\quad\quad}$
$jm = \underline{\quad\quad}$
$m\angle jkm = \underline{\quad\quad}$
$m\angle jml = \underline{\quad\quad}$
17 numeric 1 point
$m\angle jml = ?$ degrees
answer

Explanation:

Step1: Identify parallelogram properties

In parallelogram \(JKLM\), diagonals bisect each other, so \(NK=\frac{1}{2}MK\), \(NL=\frac{1}{2}JL\), \(ML=JK\), \(JM=KL\); opposite sides are parallel, so \(JM \parallel KL\), \(JK \parallel ML\). Also, \(\angle MJL = \angle KJL = 50^\circ\) (alternate interior angles, \(JK \parallel ML\)).

Step2: Find \(\angle JML\) using triangle angles

In \(\triangle JML\), \(JM \parallel KL\), so \(\angle MJL = 50^\circ\), and since \(JK \parallel ML\), \(\angle JML\) and \(\angle MJL\) are part of a triangle where we know that consecutive angles in a parallelogram are supplementary, but more directly: in \(\triangle JML\), we use the fact that \(JL\) is a transversal, and \(\angle JML + \angle MJL + \angle JLM = 180^\circ\), but since \(JK=ML\) and \(JM=KL\), \(\angle JML = 180^\circ - 2\times50^\circ\)
Expression: \(180^\circ - 2\times50^\circ = 80^\circ\)

Answer:

\(80\)