Question

find the missing factor $g$ that makes the equality true.
$18y^{3}=(g)(2y^{2})$
$g=\square$

Explanation:

Step1: Isolate G via division

$G = \frac{18y^3}{2y^2}$

Step2: Divide the constant terms

$\frac{18}{2} = 9$

Step3: Simplify the variable terms

$\frac{y^3}{y^2} = y^{3-2} = y$

Step4: Combine results

$G = 9 \times y$

Answer:

$9y$