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4. find the perimeter and area of the figure below. p = 4s a = s² 12

Question

  1. find the perimeter and area of the figure below. p = 4s a = s² 12

Explanation:

Step1: Calculate the perimeter

The outer - most shape is a square with side length \(s = 12\). The formula for the perimeter of a square is \(P=4s\). Substitute \(s = 12\) into the formula.
\(P = 4\times12=48\)

Step2: Calculate the area

The figure can be thought of as a large square with side length \(s = 12\). The formula for the area of a square is \(A=s^{2}\). Substitute \(s = 12\) into the formula.
\(A=12^{2}=144\)

Answer:

Perimeter: 48, Area: 144