Question

find the perimeter of the figure below, composed of a rectangle and two semicircles. round to the nearest tenths place. 11 6 answer attempt 1 out of 2 submit answer

Explanation:

Step1: Identify the components of the perimeter

The perimeter is composed of two lengths of the rectangle and the circumferences of two semi - circles (which is equivalent to one full - circle).

Step2: Calculate the circumference of the circle

The diameter of the circle is $d = 6$. The formula for the circumference of a circle is $C=\pi d$. So, $C = \pi\times6=6\pi$.

Step3: Calculate the total length of the two straight parts

The length of the rectangle is $l = 11$, and there are two such lengths. The total length of the two straight parts is $2\times11 = 22$.

Step4: Calculate the perimeter of the figure

The perimeter $P$ of the figure is the sum of the circumference of the circle and the total length of the two straight parts. So, $P=22 + 6\pi$.
Substitute $\pi\approx3.14$ into the formula: $P=22+6\times3.14=22 + 18.84=40.84$.
Rounding to the nearest tenths place, $P\approx40.8$.

Answer:

$40.8$