Question

find the perimeter of a triangle with sides 4 ft 6 in, 7 ft, and 5 ft 7 in. the perimeter of the triangle is \\(\square\\) ft \\(\square\\) in.

Explanation:

Step1: Convert feet to inches or inches to feet (we'll convert inches to feet for easier addition of feet first)

• 1 foot = 12 inches. So, 6 inches = $\frac{6}{12} = 0.5$ ft, 7 inches = $\frac{7}{12} \approx 0.5833$ ft.
• Now the sides in feet: 4 ft 6 in = $4 + 0.5 = 4.5$ ft, 7 ft (already in feet), 5 ft 7 in = $5 + \frac{7}{12} \approx 5 + 0.5833 = 5.5833$ ft.
• Add the feet parts: $4.5 + 7 + 5.5833 = 17.0833$ ft. Wait, maybe better to add feet and inches separately.

Step2: Add feet and inches separately

• Feet: 4 ft + 7 ft + 5 ft = 16 ft.
• Inches: 6 in + 0 in + 7 in = 13 in.
• Now, convert 13 inches to feet and inches: 13 in = 1 ft 1 in (since 12 in = 1 ft, 13 - 12 = 1 in).
• Add the feet from inches to the total feet: 16 ft + 1 ft = 17 ft. And the remaining inches: 1 in.

Wait, let's do it step by step correctly:
Perimeter of a triangle is the sum of all sides.
Side 1: 4 ft 6 in = 4*12 + 6 = 54 in.
Side 2: 7 ft = 7*12 = 84 in.
Side 3: 5 ft 7 in = 5*12 + 7 = 67 in.
Total perimeter in inches: 54 + 84 + 67 = 205 in.
Now convert 205 in to feet and inches:
205 ÷ 12 = 17 with a remainder of 1 (since 12*17 = 204, 205 - 204 = 1). So 205 in = 17 ft 1 in.

Answer:

17 ft 1 in