Question

find the product. simplify your answer.
$(4b + 2)(-3b^2 + 2b + 2)$

Explanation:

Step1: Distribute $4b$ to each term

$4b \times (-3b^2) + 4b \times 2b + 4b \times 2 = -12b^3 + 8b^2 + 8b$

Step2: Distribute $2$ to each term

$2 \times (-3b^2) + 2 \times 2b + 2 \times 2 = -6b^2 + 4b + 4$

Step3: Combine all terms

$-12b^3 + 8b^2 + 8b -6b^2 + 4b + 4$

Step4: Combine like terms

$-12b^3 + (8b^2-6b^2) + (8b+4b) + 4 = -12b^3 + 2b^2 + 12b + 4$

Answer:

$-12b^3 + 2b^2 + 12b + 4$