Question

find the real solution(s) of the equation \\(\frac{1}{3}x^{4}=27\\).
x = \\(square\\) and x = \\(square\\)

Explanation:

Step1: Isolate $x^4$ term

Multiply both sides by 3:
$$x^4 = 27 \times 3$$
$$x^4 = 81$$

Step2: Take 4th root of both sides

Recall $x^4 = 81 = 3^4 = (-3)^4$:
$$x = \pm \sqrt[4]{81}$$
$$x = \pm 3$$

Answer:

$x = 3$ and $x = -3$