Question

find the sum or difference.
$(-8xy + 3x^2 - 5y) + (4x^2 - 2y + 6xy)$
$x^2 +$
$xy +$
$\square y$

Explanation:

Step1: Remove parentheses

$(-8xy + 3x^2 - 5y) + (4x^2 - 2y + 6xy) = -8xy + 3x^2 - 5y + 4x^2 - 2y + 6xy$

Step2: Group like terms

$= (3x^2 + 4x^2) + (-8xy + 6xy) + (-5y - 2y)$

Step3: Combine like terms

$= 7x^2 - 2xy - 7y$

Answer:

$7$
$-2$
$-7$