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find the value of x that makes the quadrilateral a parallelogram. 4x + …

Question

find the value of x that makes the quadrilateral a parallelogram.
4x + 2
5x - 6
x = \square

Explanation:

Step1: Set segments equal (parallelogram rule)

In a parallelogram, diagonals bisect each other, so $4x + 2 = 5x - 6$

Step2: Isolate x variable

Subtract $4x$ from both sides: $2 = x - 6$

Step3: Solve for x

Add 6 to both sides: $x = 2 + 6 = 8$

Answer:

$8$