Question

find the value of b. pythagorean theorem: a² + b² = c² 5 in 12 in b b = √?

Explanation:

Step1: Identify values for Pythagorean theorem

Let $a = 5$, $c=12$. The Pythagorean theorem is $a^{2}+b^{2}=c^{2}$, and we want to solve for $b$. Rearranging the formula for $b$ gives $b=\sqrt{c^{2}-a^{2}}$.

Step2: Substitute values into the formula

Substitute $a = 5$ and $c = 12$ into $b=\sqrt{c^{2}-a^{2}}$. So $b=\sqrt{12^{2}-5^{2}}=\sqrt{144 - 25}$.

Step3: Calculate the value inside the square - root

$144-25 = 119$. So $b=\sqrt{119}$.

Answer:

$\sqrt{119}$