Question

find the value of y. round to the nearest tenth, if necessary.
12
y
8
y=□

Explanation:

Step1: Apply Pythagorean theorem

$$a^2 + b^2 = c^2$$
Let $a=8$, $b=y$, $c=12$. Substitute into the formula:
$$8^2 + y^2 = 12^2$$

Step2: Calculate squared values

$$64 + y^2 = 144$$

Step3: Isolate $y^2$

$$y^2 = 144 - 64$$
$$y^2 = 80$$

Step4: Solve for $y$

$$y = \sqrt{80} \approx 8.9$$

Answer:

8.9