Question

find the value of \\(\sin d\\) rounded to the nearest hundredth, if necessary.

Explanation:

Step1: Find hypotenuse $FD$

$$FD = \sqrt{5^2 + 7^2} = \sqrt{25 + 49} = \sqrt{74} \approx 8.602$$

Step2: Identify $\sin D$ ratio

$\sin D = \frac{\text{opposite side to } D}{\text{hypotenuse}} = \frac{FE}{FD}$

Step3: Calculate $\sin D$

$$\sin D = \frac{5}{\sqrt{74}} \approx \frac{5}{8.602} \approx 0.58$$

Answer:

$0.58$