Question

find the values of x and y so that the quadrilateral is a parallelogram.
$x = \square$
$y = \square$
$3y-5$
$-4x-2$
$2y+18$
$-3x+4$
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Explanation:

Step1: Set equal x-segment pairs

$-4x - 2 = -3x + 4$

Step2: Solve for x

$-4x + 3x = 4 + 2$
$-x = 6$
$x = -6$

Step3: Set equal y-segment pairs

$3y - 5 = 2y + 18$

Step4: Solve for y

$3y - 2y = 18 + 5$
$y = 23$

Answer:

$x = -6$; $y = 23$