Question

find the y-intercept, the axis of symmetry, and the vertex of the graph of the function f(x)=5x² + 5x + 11 the y-intercept is (type an ordered pair)

Explanation:

Step1: Recall y-intercept definition

The y-intercept of a function \( f(x) \) is the point where \( x = 0 \), so we substitute \( x = 0 \) into the function.
\( f(0)=5(0)^2 + 5(0)+11 \)

Step2: Calculate \( f(0) \)

Simplify the expression: \( 5(0)^2=0 \), \( 5(0)=0 \), so \( f(0)=0 + 0+11 = 11 \).
So the y - intercept is the ordered pair \( (0,11) \).

Answer:

\((0, 11)\)