QUESTION IMAGE
Question
- a flagpole casts a shadow that is 50 feet long. at the same time, you who are 64 inches tall cast a shadow that is 40 inches long. how tall is the flagpole to the nearest foot?
a. 12 feet
b. 80 feet
c. 40 feet
d. 140 feet
Question 5 (the flagpole and person shadow problem)
Step 1: Set up proportion
We can use similar triangles (since the sun's rays are parallel, the triangles formed by the flagpole, its shadow, the person, and their shadow are similar). Let \( h \) be the height of the flagpole. The ratio of height to shadow length should be equal for both. So, \(\frac{\text{Height of flagpole}}{\text{Shadow of flagpole}}=\frac{\text{Height of person}}{\text{Shadow of person}}\)
First, convert all units to inches or feet. Let's convert the flagpole's shadow to inches: \( 50 \) feet \( = 50\times12 = 600 \) inches. The person's height is \( 64 \) inches, shadow is \( 40 \) inches.
So the proportion is \(\frac{h}{600}=\frac{64}{40}\)
Step 2: Solve for \( h \)
Cross - multiply: \( 40h=64\times600 \)
Calculate \( 64\times600 = 38400 \)
Then, \( h=\frac{38400}{40}=960 \) inches. Now convert back to feet: \( 960\div12 = 80 \) feet.
- Option a: The altitude to the hypotenuse of a right triangle is the geometric mean between the segments into which it divides the hypotenuse. This is a true property of right triangles (geometric mean theorem).
- Option b: The leg of a right triangle is the geometric mean of the hypotenuse and the segment of the hypotenuse adjacent to that leg. This is also a true property from the geometric mean theorem.
- Option c: The geometric mean of two numbers \( a \) and \( b \) is \( \sqrt{ab} \), which is the product of the square roots of \( a \) and \( b \), not the product of the hypotenuse and the two legs (this is incorrect as the geometric mean in right triangles relates to the altitude and segments of hypotenuse or legs and hypotenuse segments, not the product of hypotenuse and legs).
- Option d: The geometric mean is the square root of the product of the hypotenuse and the segment of the hypotenuse adjacent to the leg (which is the same as option b, just rephrased).
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b. 80 feet