Question

a football is kicked vertically upward from a height of 5 foot with an initial speed of 70 feet per second. the formula h = 5 + 70t - 16t^2 describes the balls height above the ground, h, in feet, t seconds after it was kicked. use this formula to find the balls height 3 seconds after it was kicked. the balls height, 3 seconds after it was kicked, was feet.

Explanation:

Step1: Identify the values to substitute

We are given the formula $h = 5+70t - 16t^{2}$ and $t = 3$.

Step2: Substitute $t = 3$ into the formula

$h=5 + 70\times3-16\times3^{2}$.

Step3: Calculate the powers

$3^{2}=9$, so $h = 5+70\times3 - 16\times9$.

Step4: Calculate the multiplications

$70\times3 = 210$ and $16\times9=144$, so $h=5 + 210-144$.

Step5: Calculate the sum and difference

$5+210 = 215$, then $215-144 = 71$.

Answer:

71