Question

formulas can be manipulated through the process of solving literal equations.

1. solve for b: a = bh (area of a parallelogram)
2. solve for h: a = \frac{1}{2}bh (area of a triangle)
3. solve for d: c = \pi d (circumference of a circle)

Explanation:

Step1: Isolate b in parallelogram formula

Divide both sides of $A = bh$ by h. So $b=\frac{A}{h}$.

Step2: Isolate h in triangle formula

First, multiply both sides of $A=\frac{1}{2}bh$ by 2 to get $2A = bh$. Then divide both sides by b, so $h=\frac{2A}{b}$.

Step3: Isolate d in circle - circumference formula

Divide both sides of $C=\pi d$ by $\pi$, so $d = \frac{C}{\pi}$.

Answer:

1. $b=\frac{A}{h}$
2. $h=\frac{2A}{b}$
3. $d=\frac{C}{\pi}$