Question

forty ounces of a 50% gold alloy are mixed with 60 oz of a 30% gold alloy. find the percent concentration of the resulting gold alloy.

Explanation:

Step1: Calculate gold amount in first alloy

The first alloy is 40 oz with 50% gold. So the amount of gold is $40\times0.5 = 20$ oz.

Step2: Calculate gold amount in second alloy

The second alloy is 60 oz with 30% gold. So the amount of gold is $60\times0.3=18$ oz.

Step3: Calculate total gold amount

The total amount of gold is $20 + 18=38$ oz.

Step4: Calculate total alloy amount

The total amount of the resulting alloy is $40 + 60 = 100$ oz.

Step5: Calculate the percent - concentration

The percent - concentration of the resulting alloy is $\frac{38}{100}\times100\%=38\%$.

Answer:

38%